Python Program-3 EXAM20@cbse.com Program with Explanation

Python Program-3: EXAM20@cbse.com Program with Explanation

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Question: Find the output of the following Python program.

def display(s):
    l = len(s)
    m=""
    for i in range(0,l):
        if s[i].isupper():
            m=m+s[i].lower()
        elif s[i].isalpha():
            m=m+s[i].upper()
        elif s[i].isdigit():
            m=m+"$"
        else:
            m=m+"*"
    print(m)
display("EXAM20@cbse.com")Code language: Python (python)

Output:

exam$$*CBSE*COM

Read Also: How To Check String Contains Special Characters In Java?

Explanation:

In the above python program, we have the given String ”EXAM20@cbse.com”.

First, we have found the length of the given string by using the len( ) function and we have declared one empty string m=””. Then we have used for loop iteration.

Iteration-1:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = “”
i = 0		As i = 0 and s[0] = E, So
m=m + s[i].lower()
m = “” + s[0].lower() = “” + e = e

Iteration-2:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = e
i = 1		As i = 1 and s[1] = X, So
m = m + s[i].lower()
m = e + s[1].lower() = e + x = ex

Iteration-3:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = ex
i = 2		As i = 2 and s[2] = A, So
m = m + s[i].lower()
m = ex + s[2].lower() = ex + a = exa

Iteration-4:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = exa
i = 3		As i = 3 and s[3] = M, So
m = m + s[i].lower()
m = exa + s[3].lower() = exa + m = exam

Iteration-5:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = exam
i = 4		As i = 4 and s[4] = 2, So
m = m+”$”
m = exam + “$” = exam$

Iteration-6:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = exam$
i = 5		As i = 5 and s[5] = 0(digit), So
m = m+”$”
m = exam$ + “$” = exam$$

Iteration-7:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = exam$$
i = 6		As i = 6 and s[6] = @(Special Character), So
m = m+”*”
m = exam$$ + “*” = exam$$*

Iteration-8:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = exam$$*
i = 7		As i = 7 and s[7] = c (Small Alphabet), So
m = m + s[i].upper()
m = exam$$* + s[7].upper() = exam$$* + C = exam$$*C

Iteration-9:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = exam$$*C
i = 8		As i = 8 and s[8] = b (Small Alphabet), So
m = m + s[i].upper()
m = exam$$*C + s[8].upper() = exam$$*C + B = exam$$*CB

Iteration-10:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = exam$$*CB
i = 9		As i = 9 and s[9] = s (Small Alphabet), So
m = m + s[i].upper()
m = exam$$*CB + s[9].upper() = exam$$*CB + S = exam$$*CBS

Iteration-11:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = exam$$*CBS
i = 10		As i = 10 and s[10] = e (Small Alphabet), So
m = m + s[i].upper()
m = exam$$*CBS + s[10].upper() = exam$$*CBS + E = exam$$*CBSE

Iteration-12:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = exam$$*CBSE
i = 11		As i = 11 and s[11] = . (Special Character), So
m = m + “*”
m = exam$$*CBSE + “*” = exam$$*CBSE*

Iteration-13:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = exam$$*CBSE*
i = 12		As i = 12 and s[12] = c (Small Alphabet), So
m = m + s[i].upper()
m = exam$$*CBSE* + s[12].upper() = exam$$*CBSE* + C = exam$$*CBSE*C

Iteration-14:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = exam$$*CBSE*C
i = 13		As i = 13 and s[13] = o (Small Alphabet), So
m = m + s[i].upper()
m = exam$$*CBSE*C + s[13].upper() = exam$$*CBSE*C + O = exam$$*CBSE*CO

Iteration-15:

Current ValuesOperation
s = EXAM20@cbse.com
l = 15
m = exam$$*CBSE*CO
i = 14		As i = 14 and s[14] = m (Small Alphabet), So
m = m + s[i].upper()
m = exam$$*CBSE*CO + s[14].upper() = exam$$*CBSE*CO + M = exam$$*CBSE*COM

So as per the above iteration-15, the value of m will be exam$$*CBSE*COM. Finally, by using the print method( print(m) ), we have displayed the output to the user.

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